3(x-40)-5(x+5)=35-7(x-30)

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Solution for 3(x-40)-5(x+5)=35-7(x-30) equation: 



3(x-40)-5(x+5)=35-7(x-30)

We move all terms to the left:

3(x-40)-5(x+5)-(35-7(x-30))=0

We multiply parentheses

3x-5x-(35-7(x-30))-120-25=0



We calculate terms in parentheses: -(35-7(x-30)), so:

35-7(x-30)

determiningTheFunctionDomain
-7(x-30)+35

We multiply parentheses

-7x+210+35

We add all the numbers together, and all the variables

-7x+245

Back to the equation:

-(-7x+245)



We add all the numbers together, and all the variables

-2x-(-7x+245)-145=0

We get rid of parentheses

-2x+7x-245-145=0

We add all the numbers together, and all the variables

5x-390=0

We move all terms containing x to the left, all other terms to the right

5x=390

x=390/5

x=78

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