3(x-4+2x+5)=4(2x-2+3x)-5x

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Solution for 3(x-4+2x+5)=4(2x-2+3x)-5x equation: 



3(x-4+2x+5)=4(2x-2+3x)-5x

We move all terms to the left:

3(x-4+2x+5)-(4(2x-2+3x)-5x)=0

We add all the numbers together, and all the variables

3(3x+1)-(4(5x-2)-5x)=0

We multiply parentheses

9x-(4(5x-2)-5x)+3=0



We calculate terms in parentheses: -(4(5x-2)-5x), so:

4(5x-2)-5x

We add all the numbers together, and all the variables

-5x+4(5x-2)

We multiply parentheses

-5x+20x-8

We add all the numbers together, and all the variables

15x-8

Back to the equation:

-(15x-8)



We get rid of parentheses

9x-15x+8+3=0

We add all the numbers together, and all the variables

-6x+11=0

We move all terms containing x to the left, all other terms to the right

-6x=-11

x=-11/-6

x=1+5/6

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