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3(x-4)=5(x+)
We move all terms to the left:
3(x-4)-(5(x+))=0
We add all the numbers together, and all the variables
3(x-4)-(5(+x))=0
We multiply parentheses
3x-(5(+x))-12=0
We calculate terms in parentheses: -(5(+x)), so:We add all the numbers together, and all the variables
5(+x)
We multiply parentheses
5x
Back to the equation:
-(5x)
-2x-12=0
We move all terms containing x to the left, all other terms to the right
-2x=12
x=12/-2
x=-6
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