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3(x-4)=2x-4(x-3)
We move all terms to the left:
3(x-4)-(2x-4(x-3))=0
We multiply parentheses
3x-(2x-4(x-3))-12=0
We calculate terms in parentheses: -(2x-4(x-3)), so:We get rid of parentheses
2x-4(x-3)
We multiply parentheses
2x-4x+12
We add all the numbers together, and all the variables
-2x+12
Back to the equation:
-(-2x+12)
3x+2x-12-12=0
We add all the numbers together, and all the variables
5x-24=0
We move all terms containing x to the left, all other terms to the right
5x=24
x=24/5
x=4+4/5
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