3(x-4)=2(4+x)

Solution for 3(x-4)=2(4+x) equation:

3(x-4)=2(4+x)

We move all terms to the left:

3(x-4)-(2(4+x))=0

We add all the numbers together, and all the variables

3(x-4)-(2(x+4))=0

We multiply parentheses

3x-(2(x+4))-12=0


We calculate terms in parentheses: -(2(x+4)), so:

2(x+4)

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)


We get rid of parentheses

3x-2x-8-12=0

We add all the numbers together, and all the variables

x-20=0

We move all terms containing x to the left, all other terms to the right

x=20