3(x-4)/2=3(x+4)/10

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Solution for 3(x-4)/2=3(x+4)/10 equation:



3(x-4)/2=3(x+4)/10
We move all terms to the left:
3(x-4)/2-(3(x+4)/10)=0
We calculate fractions
3x/()+(-(3(x+4)*2)/()=0
We calculate terms in parentheses: +(-(3(x+4)*2)/(), so:
-(3(x+4)*2)/(
We multiply all the terms by the denominator
-(3(x+4)*2)
We calculate terms in parentheses: -(3(x+4)*2), so:
3(x+4)*2
We multiply parentheses
6x+24
Back to the equation:
-(6x+24)
We get rid of parentheses
-6x-24
Back to the equation:
+(-6x-24)
We get rid of parentheses
3x/()-6x-24=0
We multiply all the terms by the denominator
3x-6x*()-24*()=0
We add all the numbers together, and all the variables
3x-6x*()=0

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