3(x-4)/122x/3

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Solution for 3(x-4)/122x/3 equation:


x in (-oo:+oo)

(3*(x-4))/12 < (2*x)/3 // - (2*x)/3

(3*(x-4))/12-((2*x)/3) < 0

(3*(x-4))/12+(-2/3)*x < 0

(3*(x-4))/12+(-2*x)/3 < 0

(3^2*(x-4))/(3*12)+(-2*12*x)/(3*12) < 0

3^2*(x-4)-2*12*x < 0

-15*x-36 < 0

(-15*x-36)/(3*12) < 0

(-15*x-36)/(3*12) < 0 // * (3*12)^2

3*12*(-15*x-36) < 0

( -15*x-36 )

-15*x-36 < 0 // + 36

-15*x < 36 // : -15

x > 36/(-15)

x > -12/5

( 12 )

12 < 0

x belongs to the empty set

( 3 )

3 < 0

x belongs to the empty set

(-oo:-12/5) (-12/5:+oo) -15*x-36 + - 12 + + 3 + +

x in (-12/5:+oo)

(-12/5:+oo)

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