3(x-4)-4=2(x-4)+x

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Solution for 3(x-4)-4=2(x-4)+x equation: 


Simplifying
3(x + -4) + -4 = 2(x + -4) + x

Reorder the terms:
3(-4 + x) + -4 = 2(x + -4) + x
(-4 * 3 + x * 3) + -4 = 2(x + -4) + x
(-12 + 3x) + -4 = 2(x + -4) + x

Reorder the terms:
-12 + -4 + 3x = 2(x + -4) + x

Combine like terms: -12 + -4 = -16
-16 + 3x = 2(x + -4) + x

Reorder the terms:
-16 + 3x = 2(-4 + x) + x
-16 + 3x = (-4 * 2 + x * 2) + x
-16 + 3x = (-8 + 2x) + x

Combine like terms: 2x + x = 3x
-16 + 3x = -8 + 3x

Add '-3x' to each side of the equation.
-16 + 3x + -3x = -8 + 3x + -3x

Combine like terms: 3x + -3x = 0
-16 + 0 = -8 + 3x + -3x
-16 = -8 + 3x + -3x

Combine like terms: 3x + -3x = 0
-16 = -8 + 0
-16 = -8

Solving
-16 = -8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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