3(x-4)-4(x-4)=x+3-(x-2)

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Solution for 3(x-4)-4(x-4)=x+3-(x-2) equation:


3(x-4)-4(x-4)=x+3-(x-2)

We simplify the equation to the form, which is simple to understand 
3(x-4)-4(x-4)=x+3-(x-2)

Reorder the terms in parentheses
+(+3x-12)-4*(x-4)=x+3-(x-2)

Remove unnecessary parentheses
+3x-12-4+*(+x-4+)=+x+3-(+x-2+)

Reorder the terms in parentheses
+3x-12+(-4x+16)=x+3-(x-2)

Remove unnecessary parentheses
+3x-12-4x+16=+x+3-(+x-2+)

Remove unnecessary parentheses
+3x-12-4x+16=x+3-1x+2

We move all terms containing x to the left and all other terms to the right. 
+3x-4x-1x+1x=+3+2+12-16

We simplify left and right side of the equation. 
-1x=+1

We divide both sides of the equation by -1 to get x. 
x=-1

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