3(x-4)-4(x-3)=x+3-x+2

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Solution for 3(x-4)-4(x-3)=x+3-x+2 equation: 



3(x-4)-4(x-3)=x+3-x+2

We move all terms to the left:

3(x-4)-4(x-3)-(x+3-x+2)=0

We add all the numbers together, and all the variables

3(x-4)-4(x-3)-5=0

We multiply parentheses

3x-4x-12+12-5=0

We add all the numbers together, and all the variables

-1x-5=0

We move all terms containing x to the left, all other terms to the right

-x=5

x=5/-1

x=-5

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