3(x-4)-2=2(-2x+1)+2

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Solution for 3(x-4)-2=2(-2x+1)+2 equation: 



3(x-4)-2=2(-2x+1)+2

We move all terms to the left:

3(x-4)-2-(2(-2x+1)+2)=0

We multiply parentheses

3x-(2(-2x+1)+2)-12-2=0



We calculate terms in parentheses: -(2(-2x+1)+2), so:

2(-2x+1)+2

We multiply parentheses

-4x+2+2

We add all the numbers together, and all the variables

-4x+4

Back to the equation:

-(-4x+4)



We add all the numbers together, and all the variables

3x-(-4x+4)-14=0

We get rid of parentheses

3x+4x-4-14=0

We add all the numbers together, and all the variables

7x-18=0

We move all terms containing x to the left, all other terms to the right

7x=18

x=18/7

x=2+4/7

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