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3(x-4)-2(x-5)=2(x-5)
We move all terms to the left:
3(x-4)-2(x-5)-(2(x-5))=0
We multiply parentheses
3x-2x-(2(x-5))-12+10=0
We calculate terms in parentheses: -(2(x-5)), so:We add all the numbers together, and all the variables
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
x-(2x-10)-2=0
We get rid of parentheses
x-2x+10-2=0
We add all the numbers together, and all the variables
-1x+8=0
We move all terms containing x to the left, all other terms to the right
-x=-8
x=-8/-1
x=+8
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