3(x-4)-(x-8)=-3x+11

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Solution for 3(x-4)-(x-8)=-3x+11 equation: 



3(x-4)-(x-8)=-3x+11

We move all terms to the left:

3(x-4)-(x-8)-(-3x+11)=0

We multiply parentheses

3x-(x-8)-(-3x+11)-12=0

We get rid of parentheses

3x-x+3x+8-11-12=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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