3(x-4)+8x=21

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Solution for 3(x-4)+8x=21 equation: 



3(x-4)+8x=21

We move all terms to the left:

3(x-4)+8x-(21)=0

We add all the numbers together, and all the variables

8x+3(x-4)-21=0

We multiply parentheses

8x+3x-12-21=0

We add all the numbers together, and all the variables

11x-33=0

We move all terms containing x to the left, all other terms to the right

11x=33

x=33/11

x=3

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