3(x-4)+8x-2=10+1

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Solution for 3(x-4)+8x-2=10+1 equation: 



3(x-4)+8x-2=10+1

We move all terms to the left:

3(x-4)+8x-2-(10+1)=0

We add all the numbers together, and all the variables

3(x-4)+8x-2-11=0

We add all the numbers together, and all the variables

8x+3(x-4)-13=0

We multiply parentheses

8x+3x-12-13=0

We add all the numbers together, and all the variables

11x-25=0

We move all terms containing x to the left, all other terms to the right

11x=25

x=25/11

x=2+3/11

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