3(x-4)+7x=32

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Solution for 3(x-4)+7x=32 equation: 



3(x-4)+7x=32

We move all terms to the left:

3(x-4)+7x-(32)=0

We add all the numbers together, and all the variables

7x+3(x-4)-32=0

We multiply parentheses

7x+3x-12-32=0

We add all the numbers together, and all the variables

10x-44=0

We move all terms containing x to the left, all other terms to the right

10x=44

x=44/10

x=4+2/5

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