3(x-4)+7=9x+16

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Solution for 3(x-4)+7=9x+16 equation: 



3(x-4)+7=9x+16

We move all terms to the left:

3(x-4)+7-(9x+16)=0

We multiply parentheses

3x-(9x+16)-12+7=0

We get rid of parentheses

3x-9x-16-12+7=0

We add all the numbers together, and all the variables

-6x-21=0

We move all terms containing x to the left, all other terms to the right

-6x=21

x=21/-6

x=-3+1/2

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