3(x-4)+6=3(2-x)+6

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Solution for 3(x-4)+6=3(2-x)+6 equation: 



3(x-4)+6=3(2-x)+6

We move all terms to the left:

3(x-4)+6-(3(2-x)+6)=0

We add all the numbers together, and all the variables

3(x-4)-(3(-1x+2)+6)+6=0

We multiply parentheses

3x-(3(-1x+2)+6)-12+6=0



We calculate terms in parentheses: -(3(-1x+2)+6), so:

3(-1x+2)+6

We multiply parentheses

-3x+6+6

We add all the numbers together, and all the variables

-3x+12

Back to the equation:

-(-3x+12)



We add all the numbers together, and all the variables

3x-(-3x+12)-6=0

We get rid of parentheses

3x+3x-12-6=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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