3(x-4)+5=x+2(x-4)+1

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Solution for 3(x-4)+5=x+2(x-4)+1 equation: 


Simplifying
3(x + -4) + 5 = x + 2(x + -4) + 1

Reorder the terms:
3(-4 + x) + 5 = x + 2(x + -4) + 1
(-4 * 3 + x * 3) + 5 = x + 2(x + -4) + 1
(-12 + 3x) + 5 = x + 2(x + -4) + 1

Reorder the terms:
-12 + 5 + 3x = x + 2(x + -4) + 1

Combine like terms: -12 + 5 = -7
-7 + 3x = x + 2(x + -4) + 1

Reorder the terms:
-7 + 3x = x + 2(-4 + x) + 1
-7 + 3x = x + (-4 * 2 + x * 2) + 1
-7 + 3x = x + (-8 + 2x) + 1

Reorder the terms:
-7 + 3x = -8 + 1 + x + 2x

Combine like terms: -8 + 1 = -7
-7 + 3x = -7 + x + 2x

Combine like terms: x + 2x = 3x
-7 + 3x = -7 + 3x

Add '7' to each side of the equation.
-7 + 7 + 3x = -7 + 7 + 3x

Combine like terms: -7 + 7 = 0
0 + 3x = -7 + 7 + 3x
3x = -7 + 7 + 3x

Combine like terms: -7 + 7 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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