3(x-4)+1=2(x-5)+5x

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Solution for 3(x-4)+1=2(x-5)+5x equation: 



3(x-4)+1=2(x-5)+5x

We move all terms to the left:

3(x-4)+1-(2(x-5)+5x)=0

We multiply parentheses

3x-(2(x-5)+5x)-12+1=0



We calculate terms in parentheses: -(2(x-5)+5x), so:

2(x-5)+5x

We add all the numbers together, and all the variables

5x+2(x-5)

We multiply parentheses

5x+2x-10

We add all the numbers together, and all the variables

7x-10

Back to the equation:

-(7x-10)



We add all the numbers together, and all the variables

3x-(7x-10)-11=0

We get rid of parentheses

3x-7x+10-11=0

We add all the numbers together, and all the variables

-4x-1=0

We move all terms containing x to the left, all other terms to the right

-4x=1

x=1/-4

x=-1/4

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