3(x-4)+15=2(x-3)

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Solution for 3(x-4)+15=2(x-3) equation: 



3(x-4)+15=2(x-3)

We move all terms to the left:

3(x-4)+15-(2(x-3))=0

We multiply parentheses

3x-(2(x-3))-12+15=0



We calculate terms in parentheses: -(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We add all the numbers together, and all the variables

3x-(2x-6)+3=0

We get rid of parentheses

3x-2x+6+3=0

We add all the numbers together, and all the variables

x+9=0

We move all terms containing x to the left, all other terms to the right

x=-9

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