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3(x-4)+(5x-3)=4(2x-1)-12
We move all terms to the left:
3(x-4)+(5x-3)-(4(2x-1)-12)=0
We multiply parentheses
3x+(5x-3)-(4(2x-1)-12)-12=0
We get rid of parentheses
3x+5x-(4(2x-1)-12)-3-12=0
We calculate terms in parentheses: -(4(2x-1)-12), so:We add all the numbers together, and all the variables
4(2x-1)-12
We multiply parentheses
8x-4-12
We add all the numbers together, and all the variables
8x-16
Back to the equation:
-(8x-16)
8x-(8x-16)-15=0
We get rid of parentheses
8x-8x+16-15=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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