3(x-4)*5=3+(4x+1)

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Solution for 3(x-4)*5=3+(4x+1) equation: 



3(x-4)*5=3+(4x+1)

We move all terms to the left:

3(x-4)*5-(3+(4x+1))=0

We multiply parentheses

15x-(3+(4x+1))-60=0



We calculate terms in parentheses: -(3+(4x+1)), so:

3+(4x+1)

determiningTheFunctionDomain
(4x+1)+3

We get rid of parentheses

4x+1+3

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

15x-4x-4-60=0

We add all the numbers together, and all the variables

11x-64=0

We move all terms containing x to the left, all other terms to the right

11x=64

x=64/11

x=5+9/11

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