3(x-3)=7(2x+4)

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Solution for 3(x-3)=7(2x+4) equation: 



3(x-3)=7(2x+4)

We move all terms to the left:

3(x-3)-(7(2x+4))=0

We multiply parentheses

3x-(7(2x+4))-9=0



We calculate terms in parentheses: -(7(2x+4)), so:

7(2x+4)

We multiply parentheses

14x+28

Back to the equation:

-(14x+28)



We get rid of parentheses

3x-14x-28-9=0

We add all the numbers together, and all the variables

-11x-37=0

We move all terms containing x to the left, all other terms to the right

-11x=37

x=37/-11

x=-3+4/11

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