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3(x-3)=5x-4+5(7-x)
We move all terms to the left:
3(x-3)-(5x-4+5(7-x))=0
We add all the numbers together, and all the variables
3(x-3)-(5x-4+5(-1x+7))=0
We multiply parentheses
3x-(5x-4+5(-1x+7))-9=0
We calculate terms in parentheses: -(5x-4+5(-1x+7)), so:We add all the numbers together, and all the variables
5x-4+5(-1x+7)
determiningTheFunctionDomain 5x+5(-1x+7)-4
We multiply parentheses
5x-5x+35-4
We add all the numbers together, and all the variables
31
Back to the equation:
-(31)
3x-40=0
We move all terms containing x to the left, all other terms to the right
3x=40
x=40/3
x=13+1/3
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