3(x-3)=5x-4+4(7-x)

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Solution for 3(x-3)=5x-4+4(7-x) equation: 



3(x-3)=5x-4+4(7-x)

We move all terms to the left:

3(x-3)-(5x-4+4(7-x))=0

We add all the numbers together, and all the variables

3(x-3)-(5x-4+4(-1x+7))=0

We multiply parentheses

3x-(5x-4+4(-1x+7))-9=0



We calculate terms in parentheses: -(5x-4+4(-1x+7)), so:

5x-4+4(-1x+7)

determiningTheFunctionDomain
5x+4(-1x+7)-4

We multiply parentheses

5x-4x+28-4

We add all the numbers together, and all the variables

x+24

Back to the equation:

-(x+24)



We get rid of parentheses

3x-x-24-9=0

We add all the numbers together, and all the variables

2x-33=0

We move all terms containing x to the left, all other terms to the right

2x=33

x=33/2

x=16+1/2

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