3(x-3)=4x+40

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Solution for 3(x-3)=4x+40 equation:



3(x-3)=4x+40
We move all terms to the left:
3(x-3)-(4x+40)=0
We multiply parentheses
3x-(4x+40)-9=0
We get rid of parentheses
3x-4x-40-9=0
We add all the numbers together, and all the variables
-1x-49=0
We move all terms containing x to the left, all other terms to the right
-x=49
x=49/-1
x=-49

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