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3(x-3)=4(x+5)-18
We move all terms to the left:
3(x-3)-(4(x+5)-18)=0
We multiply parentheses
3x-(4(x+5)-18)-9=0
We calculate terms in parentheses: -(4(x+5)-18), so:We get rid of parentheses
4(x+5)-18
We multiply parentheses
4x+20-18
We add all the numbers together, and all the variables
4x+2
Back to the equation:
-(4x+2)
3x-4x-2-9=0
We add all the numbers together, and all the variables
-1x-11=0
We move all terms containing x to the left, all other terms to the right
-x=11
x=11/-1
x=-11
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