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3(x-3)=34-2(x+4)
We move all terms to the left:
3(x-3)-(34-2(x+4))=0
We multiply parentheses
3x-(34-2(x+4))-9=0
We calculate terms in parentheses: -(34-2(x+4)), so:We get rid of parentheses
34-2(x+4)
determiningTheFunctionDomain -2(x+4)+34
We multiply parentheses
-2x-8+34
We add all the numbers together, and all the variables
-2x+26
Back to the equation:
-(-2x+26)
3x+2x-26-9=0
We add all the numbers together, and all the variables
5x-35=0
We move all terms containing x to the left, all other terms to the right
5x=35
x=35/5
x=7
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