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3(x-3)=3(2x-3)
We move all terms to the left:
3(x-3)-(3(2x-3))=0
We multiply parentheses
3x-(3(2x-3))-9=0
We calculate terms in parentheses: -(3(2x-3)), so:We get rid of parentheses
3(2x-3)
We multiply parentheses
6x-9
Back to the equation:
-(6x-9)
3x-6x+9-9=0
We add all the numbers together, and all the variables
-3x=0
x=0/-3
x=0
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