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3(x-3)=2-(x+11)
We move all terms to the left:
3(x-3)-(2-(x+11))=0
We multiply parentheses
3x-(2-(x+11))-9=0
We calculate terms in parentheses: -(2-(x+11)), so:We get rid of parentheses
2-(x+11)
determiningTheFunctionDomain -(x+11)+2
We get rid of parentheses
-x-11+2
We add all the numbers together, and all the variables
-1x-9
Back to the equation:
-(-1x-9)
3x+1x+9-9=0
We add all the numbers together, and all the variables
4x=0
x=0/4
x=0
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