3(x-3)=2(x+1)-11

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Solution for 3(x-3)=2(x+1)-11 equation: 



3(x-3)=2(x+1)-11

We move all terms to the left:

3(x-3)-(2(x+1)-11)=0

We multiply parentheses

3x-(2(x+1)-11)-9=0



We calculate terms in parentheses: -(2(x+1)-11), so:

2(x+1)-11

We multiply parentheses

2x+2-11

We add all the numbers together, and all the variables

2x-9

Back to the equation:

-(2x-9)



We get rid of parentheses

3x-2x+9-9=0

We add all the numbers together, and all the variables

x=0

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