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3(x-3)=1+5(x+6)
We move all terms to the left:
3(x-3)-(1+5(x+6))=0
We multiply parentheses
3x-(1+5(x+6))-9=0
We calculate terms in parentheses: -(1+5(x+6)), so:We get rid of parentheses
1+5(x+6)
determiningTheFunctionDomain 5(x+6)+1
We multiply parentheses
5x+30+1
We add all the numbers together, and all the variables
5x+31
Back to the equation:
-(5x+31)
3x-5x-31-9=0
We add all the numbers together, and all the variables
-2x-40=0
We move all terms containing x to the left, all other terms to the right
-2x=40
x=40/-2
x=-20
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