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3(x-3)-9=-2(-6x+6)-5x
We move all terms to the left:
3(x-3)-9-(-2(-6x+6)-5x)=0
We multiply parentheses
3x-(-2(-6x+6)-5x)-9-9=0
We calculate terms in parentheses: -(-2(-6x+6)-5x), so:We add all the numbers together, and all the variables
-2(-6x+6)-5x
We add all the numbers together, and all the variables
-5x-2(-6x+6)
We multiply parentheses
-5x+12x-12
We add all the numbers together, and all the variables
7x-12
Back to the equation:
-(7x-12)
3x-(7x-12)-18=0
We get rid of parentheses
3x-7x+12-18=0
We add all the numbers together, and all the variables
-4x-6=0
We move all terms containing x to the left, all other terms to the right
-4x=6
x=6/-4
x=-1+1/2
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