3(x-3)-5(x-2)=4(2x-1)-5

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Solution for 3(x-3)-5(x-2)=4(2x-1)-5 equation: 



3(x-3)-5(x-2)=4(2x-1)-5

We move all terms to the left:

3(x-3)-5(x-2)-(4(2x-1)-5)=0

We multiply parentheses

3x-5x-(4(2x-1)-5)-9+10=0



We calculate terms in parentheses: -(4(2x-1)-5), so:

4(2x-1)-5

We multiply parentheses

8x-4-5

We add all the numbers together, and all the variables

8x-9

Back to the equation:

-(8x-9)



We add all the numbers together, and all the variables

-2x-(8x-9)+1=0

We get rid of parentheses

-2x-8x+9+1=0

We add all the numbers together, and all the variables

-10x+10=0

We move all terms containing x to the left, all other terms to the right

-10x=-10

x=-10/-10

x=1

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