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3(x-3)-2(x-5)-5=x+2
We move all terms to the left:
3(x-3)-2(x-5)-5-(x+2)=0
We multiply parentheses
3x-2x-(x+2)-9+10-5=0
We get rid of parentheses
3x-2x-x-2-9+10-5=0
We add all the numbers together, and all the variables
-6!=0
There is no solution for this equation
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