3(x-3)-12=(x-6)+10

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Solution for 3(x-3)-12=(x-6)+10 equation: 



3(x-3)-12=(x-6)+10

We move all terms to the left:

3(x-3)-12-((x-6)+10)=0

We multiply parentheses

3x-((x-6)+10)-9-12=0



We calculate terms in parentheses: -((x-6)+10), so:

(x-6)+10

We get rid of parentheses

x-6+10

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)



We add all the numbers together, and all the variables

3x-(x+4)-21=0

We get rid of parentheses

3x-x-4-21=0

We add all the numbers together, and all the variables

2x-25=0

We move all terms containing x to the left, all other terms to the right

2x=25

x=25/2

x=12+1/2

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