3(x-3)-(9x-6)=3(4x+6)

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Solution for 3(x-3)-(9x-6)=3(4x+6) equation: 



3(x-3)-(9x-6)=3(4x+6)

We move all terms to the left:

3(x-3)-(9x-6)-(3(4x+6))=0

We multiply parentheses

3x-(9x-6)-(3(4x+6))-9=0

We get rid of parentheses

3x-9x-(3(4x+6))+6-9=0



We calculate terms in parentheses: -(3(4x+6)), so:

3(4x+6)

We multiply parentheses

12x+18

Back to the equation:

-(12x+18)



We add all the numbers together, and all the variables

-6x-(12x+18)-3=0

We get rid of parentheses

-6x-12x-18-3=0

We add all the numbers together, and all the variables

-18x-21=0

We move all terms containing x to the left, all other terms to the right

-18x=21

x=21/-18

x=-1+1/6

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