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3(x-3)+6=3(2x-3)
We move all terms to the left:
3(x-3)+6-(3(2x-3))=0
We multiply parentheses
3x-(3(2x-3))-9+6=0
We calculate terms in parentheses: -(3(2x-3)), so:We add all the numbers together, and all the variables
3(2x-3)
We multiply parentheses
6x-9
Back to the equation:
-(6x-9)
3x-(6x-9)-3=0
We get rid of parentheses
3x-6x+9-3=0
We add all the numbers together, and all the variables
-3x+6=0
We move all terms containing x to the left, all other terms to the right
-3x=-6
x=-6/-3
x=+2
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