3(x-3)+4x=2(X+1)+3

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Solution for 3(x-3)+4x=2(X+1)+3 equation: 



3(x-3)+4x=2(x+1)+3

We move all terms to the left:

3(x-3)+4x-(2(x+1)+3)=0

We add all the numbers together, and all the variables

4x+3(x-3)-(2(x+1)+3)=0

We multiply parentheses

4x+3x-(2(x+1)+3)-9=0



We calculate terms in parentheses: -(2(x+1)+3), so:

2(x+1)+3

We multiply parentheses

2x+2+3

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We add all the numbers together, and all the variables

7x-(2x+5)-9=0

We get rid of parentheses

7x-2x-5-9=0

We add all the numbers together, and all the variables

5x-14=0

We move all terms containing x to the left, all other terms to the right

5x=14

x=14/5

x=2+4/5

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