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3(x-3)+2=6x-3(3+x)
We move all terms to the left:
3(x-3)+2-(6x-3(3+x))=0
We add all the numbers together, and all the variables
3(x-3)-(6x-3(x+3))+2=0
We multiply parentheses
3x-(6x-3(x+3))-9+2=0
We calculate terms in parentheses: -(6x-3(x+3)), so:We add all the numbers together, and all the variables
6x-3(x+3)
We multiply parentheses
6x-3x-9
We add all the numbers together, and all the variables
3x-9
Back to the equation:
-(3x-9)
3x-(3x-9)-7=0
We get rid of parentheses
3x-3x+9-7=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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