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3(x-3)+12=2(x+14)
We move all terms to the left:
3(x-3)+12-(2(x+14))=0
We multiply parentheses
3x-(2(x+14))-9+12=0
We calculate terms in parentheses: -(2(x+14)), so:We add all the numbers together, and all the variables
2(x+14)
We multiply parentheses
2x+28
Back to the equation:
-(2x+28)
3x-(2x+28)+3=0
We get rid of parentheses
3x-2x-28+3=0
We add all the numbers together, and all the variables
x-25=0
We move all terms containing x to the left, all other terms to the right
x=25
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