3(x-3)*4x=5

Solution for 3(x-3)*4x=5 equation:

3(x-3)*4x=5

We move all terms to the left:

3(x-3)*4x-(5)=0

We multiply parentheses

12x^2-36x-5=0

a = 12; b = -36; c = -5;
Δ = b2-4ac
Δ = -362-4·12·(-5)
Δ = 1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1536}=\sqrt{256*6}=\sqrt{256}*\sqrt{6}=16\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-16\sqrt{6}}{2*12}=\frac{36-16\sqrt{6}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+16\sqrt{6}}{2*12}=\frac{36+16\sqrt{6}}{24}
$