3(x-20)=2(x+10)

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Solution for 3(x-20)=2(x+10) equation: 



3(x-20)=2(x+10)

We move all terms to the left:

3(x-20)-(2(x+10))=0

We multiply parentheses

3x-(2(x+10))-60=0



We calculate terms in parentheses: -(2(x+10)), so:

2(x+10)

We multiply parentheses

2x+20

Back to the equation:

-(2x+20)



We get rid of parentheses

3x-2x-20-60=0

We add all the numbers together, and all the variables

x-80=0

We move all terms containing x to the left, all other terms to the right

x=80

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