3(x-2+12)=2(x+5)

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Solution for 3(x-2+12)=2(x+5) equation: 



3(x-2+12)=2(x+5)

We move all terms to the left:

3(x-2+12)-(2(x+5))=0

We add all the numbers together, and all the variables

3(x+10)-(2(x+5))=0

We multiply parentheses

3x-(2(x+5))+30=0



We calculate terms in parentheses: -(2(x+5)), so:

2(x+5)

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We get rid of parentheses

3x-2x-10+30=0

We add all the numbers together, and all the variables

x+20=0

We move all terms containing x to the left, all other terms to the right

x=-20

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