3(x-2)=7x+12

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Solution for 3(x-2)=7x+12 equation: 



3(x-2)=7x+12

We move all terms to the left:

3(x-2)-(7x+12)=0

We multiply parentheses

3x-(7x+12)-6=0

We get rid of parentheses

3x-7x-12-6=0

We add all the numbers together, and all the variables

-4x-18=0

We move all terms containing x to the left, all other terms to the right

-4x=18

x=18/-4

x=-4+1/2

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