3(x-2)=7(x-5)+1

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Solution for 3(x-2)=7(x-5)+1 equation: 



3(x-2)=7(x-5)+1

We move all terms to the left:

3(x-2)-(7(x-5)+1)=0

We multiply parentheses

3x-(7(x-5)+1)-6=0



We calculate terms in parentheses: -(7(x-5)+1), so:

7(x-5)+1

We multiply parentheses

7x-35+1

We add all the numbers together, and all the variables

7x-34

Back to the equation:

-(7x-34)



We get rid of parentheses

3x-7x+34-6=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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