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3(x-2)=4(31/2x)
We move all terms to the left:
3(x-2)-(4(31/2x))=0
Domain of the equation: 2x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3(x-2)-(4(+31/2x))=0
We multiply parentheses
3x-(4(+31/2x))-6=0
We multiply all the terms by the denominator
3x*2x))-(4(-6*2x))+31=0
Wy multiply elements
6x^2-12x=0
a = 6; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·6·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*6}=\frac{0}{12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*6}=\frac{24}{12} =2 $
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