3(x-2)=3-(4x-33)

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Solution for 3(x-2)=3-(4x-33) equation: 



3(x-2)=3-(4x-33)

We move all terms to the left:

3(x-2)-(3-(4x-33))=0

We multiply parentheses

3x-(3-(4x-33))-6=0



We calculate terms in parentheses: -(3-(4x-33)), so:

3-(4x-33)

determiningTheFunctionDomain
-(4x-33)+3

We get rid of parentheses

-4x+33+3

We add all the numbers together, and all the variables

-4x+36

Back to the equation:

-(-4x+36)



We get rid of parentheses

3x+4x-36-6=0

We add all the numbers together, and all the variables

7x-42=0

We move all terms containing x to the left, all other terms to the right

7x=42

x=42/7

x=6

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