3(x-2)=12(x-4)

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Solution for 3(x-2)=12(x-4) equation: 



3(x-2)=12(x-4)

We move all terms to the left:

3(x-2)-(12(x-4))=0

We multiply parentheses

3x-(12(x-4))-6=0



We calculate terms in parentheses: -(12(x-4)), so:

12(x-4)

We multiply parentheses

12x-48

Back to the equation:

-(12x-48)



We get rid of parentheses

3x-12x+48-6=0

We add all the numbers together, and all the variables

-9x+42=0

We move all terms containing x to the left, all other terms to the right

-9x=-42

x=-42/-9

x=4+2/3

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